Jeopardy! Greatest of All Time: Who Ya Rooting For?

Coming up next week on ABC Prime Time, the special tournament featuring the three greatest Jeopardy! players of all time, the GOATs: Brad Rutter, Ken Jennings and James Holzhauer.

Here’s what you need to know so that you won’t miss a minute. The first three matches are scheduled to begin at 8 p.m. Eastern Standard Time*, as follows:

TUESDAY, JANUARY 7, 2020
WEDNESDAY, JANUARY 8, 2020
THURSDAY, JANUARY 9, 2020

*7 p.m. Central
check your local listing for Pacific and Mountain time

Check the listings in advance for your ABC station and, if you record them, set up your DVR for these shows as a separate series.

Each show is an hour long with two complete Jeopardy! games back-to back. The winner of each match will be decided by their total point score of the two games. Each 2-part match counts as one win and the first player to win three matches will be declared JEOPARDY! THE GREATEST OF ALL TIME and will win ONE MILLION DOLLARS. The two non-winners will each receive $250,000.

If it takes more than 3 matches to declare a winner, another match will air on Friday, the 10th. If that doesn’t do it, more matches will be air the following week until one player has won three.

These games will air in addition to the regular daily game.

So, tell us now, which of the Jeopardy! GOATS are ya rootin’ for?

$4,688,436 – Brad Rutter, the leader in all-time winnings, who has never been defeated by another human. Brad first appeared on Jeopardy! when the 5-day champ rule was in effect and won $55,102. He won all the rest of that money in tournaments!

$3,370,700 – Ken Jennings, the leader in most consecutive games won (74), and highest winnings in regular game play ($2,520,700)

$2,712,216 – James Holzhauer, who won $2,462,216 in his 32-game run, almost toppling Ken Jennings’ record and also won the 2019 Tournament of Champions.